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A.正确
B.错误
A.正确
B.错误
第1题
A.A
B.B
C.C
D.D
E.E
第2题
A.A
B.B
C.C
D.D
E.E
第3题
A. Right-click the connection, and click Properties. Modify the Provider property of the data connection.
B. Click the Change button, and change the data provider for the selected data source.
C. Click the Advanced button, and change the Data Source property to the target provider.
D. Click the Advanced button, and change the Application Name property to the target provider.
第4题
A.The SELECT statement is syntactically accurate.
B.The SELECT statement does not work because there is no HAVING clause.
C.The SELECT statement does not work because the column specified in the GROUP BY clause is not in the SELECT list.
D.The SELECT statement does not work because the GROUP BY clause should be in the main query and not in the subquery.
第5题
A.SELECT last_name, department_name FROM employees NATURAL JOIN departments;
B.SELECT last_name, department_name FROM employees JOIN departments ;
C.SELECT last_name, department_name FROM employees e JOIN departments d ON (e.department_id = d.department_id);
D.SELECT last_name, department_name FROM employees e RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);
E.SELECT last_name, department_name FROM employees FULL JOIN departments ON (e.department_id = d.department_id);
F.SELECT last_name, department_name FROM employees e LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);
第6题
A.SELECT * FROM employees where salary > (SELECT MIN(salary) FROM employees GROUP BY department_id);
B.SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department_id);
C.SELECT distinct department_id FROM employees WHERE salary > ANY (SELECT AVG(salary) FROM employees GROUP BY department_id);
D.SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY department_id);
E.SELECT last_name FROM employees WHERE salary > ANY (SELECT MAX(salary) FROM employees GROUP BY department_id);
F.SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY AVG(SALARY));
第7题
A.SELECT * FROM employees where salary > (SELECT MIN(salary) FROM employees GROUP BY department_id);
B.SELECT * FROM employees WHERE salary = (SELECT AVG(salary) FROM employees GROUP BY department_id);
C.SELECT distinct department_id FROM employees WHERE salary > ANY (SELECT AVG(salary) FROM employees GROUP BY department_id);
D.SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY department_id);
E.SELECT last_name FROM employees WHERE salary > ANY (SELECT MAX(salary) FROM employees GROUP BY department_id);
F.SELECT department_id FROM employees WHERE salary > ALL (SELECT AVG(salary) FROM employees GROUP BY AVG(SALARY));
第8题
You want to retrieve all employees, whether or not they have matching departments in the departments table. Which query would you use?()
A. SELECT last_name, department_name FROM employees NATURAL JOIN departments;
B. SELECT last_name, department_name FROM employees JOIN departments ;
C. SELECT last_name, department_name FROM employees e JOIN departments d ON (e.department_id = d.department_id);
D. SELECT last_name, department_name FROM employees e RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);
E. SELECT last_name, department_name FROM employees FULL JOIN departments ON (e.department_id = d.department_id);
F . SELECT last_name, department_name FROM employees e LEFT OUTER JOIN departments d ON (e.department_id = d.department_id)
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