银行经营管理的流动性风险包括()。

BY salary DESC; SELECT last_name, salary, hire_dateFROM EMPOLYEES ORDER BY 2 DESC; What is true about them？ （）

A. The two statements produce identical results.

B. The second statement returns a syntax error.

C. There is no need to specify DESC because the results are sorted in descending order by default.

D. The two statements can be made to produce identical results by adding a column alias for the salary column in the second SQL statement.

The EMPLOYEES table contains these columns:LAST_NAME VARCHAR2 (25)SALARY NUMBER (6,2)COMMISSION_PCT NUMBER (6)You need to write a query that will produce these results:1. Display the salary multiplied by the commission_pct.2. Exclude employees with a zero commission_pct.3. Display a zero for employees with a null commission value. Evaluate the SQL statement:SELECT LAST_NAME, SALARY*COMMISSION_PCT FROM EMPLOYEESWHERE COMMISSION_PCT IS NOT NULL;What does the statement provide？ （）

A. All of the desired results

B. Two of the desired results

C. One of the desired results

D. An error statement

A. The two statements produce identical results.

B. The second statement returns a syntax error.

C. There is no need to specify DESC because the results are sorted in descending order by default.

D. The two statements can be made to produce identical results by adding a column alias for the salary column in the second SQL statement.

A. SELECT &1, "&2" FROM &3 WHERE last_name = ‘&8‘;

B. SELECT &1, ‘&2‘ FROM &3 WHERE ‘& last_name = ‘&8‘;

C. SELECT &1, &2 FROM &3 WHERE last_name = ‘&8‘;

D. SELECT &1, ‘&2‘ FROM EMP WHERE last_name = ‘&8‘;

A. SELECT last_name FROM EMP WHERE last_ name LIKE ‘_A%‘;

B. SELECT last_name FROM EMP WHERE last name =‘*A%‘

C. SELECT last_name FROM EMP WHERE last name =‘_A%‘;

D. SELECT last_name FROM EMP WHERE last name LIKE ‘*A%‘

The EMPLOYEE tables has these columns:LAST_NAME VARCHAR2(35)SALARY NUMBER(8,2)COMMISSION_PCT NUMBER(5,2)You want to display the name and annual salary multiplied by the commission_pct for all employees. For records that have a NULL commission_pct, a zero must be displayed against the calculated column.Which SQL statement displays the desired results？（）

A. SELECT last_name, (salary * 12) * commission_pct FROM EMPLOYEES;

B. SELECT last_name, (salary * 12) * IFNULL(commission_pct, 0) FROM EMPLOYEES;

C. SELECT last_name, (salary * 12) * NVL2(commission_pct, 0) FROM EMPLOYEES;

D. SELECT last_name, (salary * 12) * NVL(commission_pct, 0) FROM EMPLOYEES;

plied by the commission_pct for all employees. For records that have a NULL commission_pct, a zero must be displayed against the calculated column.Which SQL statement displays the desired results？（）

A. SELECT last_name, (salary * 12) * commission_pct FROM EMPLOYEES;

B. SELECT last_name, (salary * 12) * IFNULL(commission_pct, 0) FROM EMPLOYEES;

C. SELECT last_name, (salary * 12) * NVL2(commission_pct, 0) FROM EMPLOYEES;

D. SELECT last_name, (salary * 12) * NVL(commission_pct, 0) FROM EMPLOYEES;

The EMPLOYEES table contains these columns:EMPLOYEE_ID NUMBER(4)LAST_NAME VARCHAR2 (25)JOB_ID VARCHAR2(10)You want to search for strings that contain ‘SA_‘ in the JOB_ID column. Which SQL statement do you use？（）

A. SELECT employee_id, last_name, job_id FROM employees WHERE job_id LIKE ‘%SA\_%‘ESCAPE‘\‘;

B. SELECT employee_id, last_name, job_id FROM employees WHERE job_id LIKE ‘%SA_‘;

C. SELECT employee_id, last_name, job_id FROM employees WHERE job_id LIKE ‘%SA_‘ESCAPE‘\‘;

D. SELECT employee_id, last_name, job_id FROM employees WHERE job_id ‘%SA_‘;