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![设函数f(x)在区间[0,2]上具有二阶导数,且|f(x)|≤1,|f"(x)|≤1,x∈[0,2].证明:对任意x∈[0,2],|f'(x)|](https://img2.soutiyun.com/shangxueba/askcard/2024-02/20/836/20240220195502528.jpg)
[主观题]
设函数f(x)在区间[0,2]上具有二阶导数,且|f(x)|≤1,|f"(x)|≤1,x∈[0,2].证明:对任意x∈[0,2],|f'(x)|
设函数f(x)在区间[0,2]上具有二阶导数,且|f(x)|≤1,|f"(x)|≤1,x∈[0,2].证明:对任意x∈[0,2],|f'(x)|≤2成立.
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设函数f(x)在区间[0,2]上具有二阶导数,且|f(x)|≤1,|f"(x)|≤1,x∈[0,2].证明:对任意x∈[0,2],|f'(x)|≤2成立.
第2题
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