我国现行规范采用（)作为混凝土结构的设计方法。.A．以概率理论为基础的极限状态B．安全系数法C．经

A.IEEE802.10

B.MisconfiguredNIC

C.Userconfiguration

D.IEEE802.1Q

E.Noneoftheotheralternativesapply

A.Switch2isconfiguredforonlyVLAN1

B.Switch2isaVTPserverinadifferentdomain

C.Switch2isaVTPserverintheCompanydomain

D.Switch2isnotaVTPdomain.

E.Switch2hasalowerVTPconfigurationrevisionnumberthanthecurrentVTPrevision

F.Switch2hasahigherVTPconfigurationrevisionnumberthanthecurrentVTPrevision

A.Physicalmanagementoftheswitch

B.Logicalmanagementoftheswitch

C.In-bandmanagementoftheswitch

D.Out-of-bandmanagementoftheswitch

A.ReloadtheactiveVLANconfiguration

B.Cleartheaffectedportandbringitupagain

C.ExplicitlysetthetrunkfortheVLANtobeon

D.RemovealltheVLANsset

betweenthetwoVLANs.Eachswitchhasidenticalmodules，softwarerevisionsandVLANconfigurationinformation.SpanningtreeprotocolisdisabledonallVLANs.Whatisprobablycausingthisproblem？（）

A.ThelinkisusingIEEE802.1Qprotocol

B.ThelinkisusingIEEE802.1Eprotocol

C.Spanningtreeisdisabled

D.Notenoughinformationtodetermine

E.ThenativeVLANinformationisidenticalateachendofthelink

F.ThenativeVLANinformationisdifferentateachendofthelink

Inthenetwork，VLANTrunkingProtocol（VTP）isrunningwithadomainnameofR1.VLANs1，2，3，4，5，10，20areactiveonthenetwork.Suddenlythewholenetworkgoesdown.NotrafficisbeingpassedonVLANs2，3，4，5，10，20.However，trafficpassesonVLAN1andindicatesallswitchesareoperational.Rightbeforethenetworkproblemoccurred；aswitchnamedSW13wastakenoutofthelabandaddedtothenetwork.WhatthreeconfigurationissuesonSW13couldbecausingthenetworkoutage？（）

A.TheMD5digestsdonotmatch

B.SwitchCK-P1S1isintransparentmode

C.Thepasswordsdonotmatch

D.TheVTPdomainsaredifferent

A.Ina6to4tunnel，thefirsttwobytesoftheIPv6addresswillbe0x2002andthenextfourbyteswillbethehexadecimalequivalentoftheIPv4address

B.Ina6to4tunnel，theIPv4address192.168.99.1wouldbeconvertedtothe2002：1315：4463：1：：/64IPv6address

C.Ina6to4tunnel，theIPv4address192.168.99.1wouldbeconvertedtothe2002：c0a8：6301：：/48IPv6address

D.Ina6to4tunnel，thefirsttwobytesoftheIPv6addresswillbelocallyderivedandthenexttwobyteswillbethehexadecimalequivalentoftheIPv4address

E.Ina6to4tunnel，theIPv4address192.168.99.1wouldbeconvertedtothe2002：c0a8：6301：：/16IPv6address

A.6to4isamanualtunnelmethod

B.PrependingareservedIPv6codetothehexadecimalrepresentationof192.168.0.1facilitates6to4tunneling

C.Each6to4sitereceivesa/48prefixina6to4tunnel

D.2002：：/48istheaddressrangespecificallyassignedto6to4

E.Prepending0x2002withtheIPv4addresscreatesanIPv6addressthatisusedin6to4tunneling

A.OnlyOSPFversion3canbeutilizedforroutingIPv4andIPv6

B.IPv4andIPv6networkscanberoutedsimultaneously

C.IPv6canberoutedusingthesameroutingprotocolversionsasIPv4

D.ArouterroutingforIPv6andIPv4mustconvertIPv4packetstoIPv6packetstoroutethem

E.Noneoftheotheralternativesapply